One hundred watts inverter circuit operating and programs.

 

An inverter is a small circuit that converts the direct cutting-edge (DC) to switch modern (AC). The energy of a battery is transformed into primary voltages or alternating current voltages we can use AC electricity for digital home equipment like television, cell phones, laptop etc. The simple feature of an inverter is to convert DC to AC. A step-up transformer is used to create essential voltages. In this article, we are going to sketch a hundred watt inverter circuit.

 

 

Block Diagram of an Inverter

 

According to the block diagram, the battery supply is fed into the MOSFET driver, which oscillates the DC current, and the resulting oscillation is fed into the step-up transformer, which then supplies AC power. 

 

 

Components Required for 100 watts inverter circuit

 

• Resistor – 330 ohm – 1
• Resistor – 220 ohm – 2
• Resistor – 1k ohm – 2
• Resistor – 390k ohm – 1
• IC – CD4047 – 1
• MOSFET IRF540 -2
• Diode – 1N4007 – 1
• Switch – 1
• Capacitor – 0.01uF – 1
• Capacitor – 0.1uF
• Transformer – 150VA – 1
• 12v Battery-1

 

Circuit Diagram of inverter circuit

 

 

A Hundred Watt Inverter Circuit in Action

 

 

CD4047 is a multi-vibrator with very low energy consumption. It can operate as a mono-stable multi-vibrator as well as a steady multi-vibrator.It operates in free jogging or gated position modes in a steady multi-vibrator mode and also provides precise frequency stability.It generates a 50% responsibility cycle that creates a pulse that is utilised for inverter circuits. This is the predominant use of IC CD4047.

 

IRF540 is an N-channel MOSFET that is commonly used in switching regulators, switching converters, relay drivers, etc. The use of a MOSFET in the INVERTER circuit is motivated by the fact that it is an excessive switching transistor that operates at very low gate force strengths and has an excessive input impedance.

 

 

Explanation of a hundred-watt inverter circuit

 

• In this 100-watt inverter circuit layout, we see that a 12V battery is connected to the diode LED as well as pins 8, PIN 7, PIN 9, and PIN 12 of the IC.The nice energy grant is also to pins 4,5,6, and 14, which are secure and complement the IC CD 4047's stability.The basic function of the diode in the circuit is to stop reverse current.

 

 

• The CD4047 IC operates in a secure multi-vibrator mode.To operate it in a secure multi-vibrator mode, we need a capacitor connected between the IC's pins 1 and 3.Pin2 is connected via a resistor and a variable resistor to alternate the output frequency of the inverter. The pins 10 and 11 of the IC are linked to the gate of the IRF540. The output frequencies of pins 10 and 11 generate frequencies with a 50% obligation cycle.

 

 

• The output frequency is related to the MOSFET via 220 ohm resistors, which will assist in retarding the loading of the MOSFET. Each MOSFET (IRF540) generates today's primary alternating current current.MOSFETs serve as two digital switches in this case.

 

 

• The output AC is given to the step-up transformer of the secondary coil from this coil to amplify AC voltage. These voltages rely on the strength of the transformer.

 

• In this way, DC is transformed into AC current.

 

 

Notes

Battery can be a 12V/ 6Ah lead-acid battery.

MOSFET must be fitted one proper heat sink to protect.

Transformer can be a 9-0-9 V primary, 230V/110v secondary, 150VA transformer.

There is a very simple one suitable for low-grade applications not for high watts output.